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    Conversion field-current next up previous contents
    Next: Conversion from Band Width Up: Calibration Previous: Calibration   Contents



    Conversion field-current

    3.5The conversion between the field $ H$ in G and the setpoint current $ I$ in Amps is

    $\displaystyle H=A+BI,$ (3.1)

    where $ A$ =0.175$ \pm$ 0.046 G; $ B$ =2.2131$ \pm$ 0.0019 G/Amp.
    BNMR Web Site 2006-06-30



    Page last modified: 07/23/09 02:45 by Andrew MacFarlane.